3^x+3^x+1+(3^x)/8=11/8

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Solution for 3^x+3^x+1+(3^x)/8=11/8 equation:



3^x+3^x+1+(3^x)/8=11/8
We move all terms to the left:
3^x+3^x+1+(3^x)/8-(11/8)=0
We add all the numbers together, and all the variables
3^x+3^x+3^x/8+1-(+11/8)=0
We get rid of parentheses
3^x+3^x+3^x/8+1-11/8=0
We multiply all the terms by the denominator
3^x*8+3^x*8+3^x-11+1*8=0
We add all the numbers together, and all the variables
3^x*8+3^x*8+3^x-3=0
Wy multiply elements
24x+24x+3^x-3=0
We add all the numbers together, and all the variables
48x+3^x-3=0
We move all terms containing x to the left, all other terms to the right
48x+3^x=3

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